30v^2=19v+63

Solution for 30v^2=19v+63 equation:

30v^2=19v+63

We move all terms to the left:

30v^2-(19v+63)=0

We get rid of parentheses

30v^2-19v-63=0

a = 30; b = -19; c = -63;
Δ = b2-4ac
Δ = -192-4·30·(-63)
Δ = 7921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7921}=89$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-89}{2*30}=\frac{-70}{60}
=-1+1/6
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+89}{2*30}=\frac{108}{60}
=1+4/5
$